hi all!

i calculated the possibility that attackers and defencer(?) will win. ill show below.

(if someone already calculated, sorry)

a = the number of dices that attacker owns.
d = the number of dices that defencer owns.
p(a,b) = the possibility that attacker will win.


p(8,8) = 0.470
p(8,7) = 0.673
p(8.6) = 0.843
p(8,5) = 0.947
p(8,4) = 0.989
p(8,3) = 0.999 (0.9990)
p(8.2) = 0.999 (0.99997)
p(8,1) = 1.000

p(7,8) = 0.274
p(7,7) = 0.468
p(7,6) = 0.685
p(7,5) = 0.862
p(7,4) = 0.961
p(7,3) = 0.994
p(7,2) = 0.999 (0.9998)
p(7,1) = 1.000

p(6,8) = 0.121
p(6,7) = 0.259
p(6,6) = 0.466
p(6,5) = 0.699
p(6,4) = 0.883
p(6,3) = 0.975
p(6,2) = 0.998
p(6,1) = 0.999 (0.99995)

p(5,8) = 0.036
p(5,7) = 0.103
p(5,6) = 0.242
p(5,5) = 0.463
p(5,4) = 0.717
p(5,3) = 0.909
p(5,2) = 0.987
p(5,1) = 0.999 (0.9998)

p(4,8) = 0.006
p(4,7) = 0.025
p(4,6) = 0.083
p(4,5) = 0.220
p(4,4) = 0.459
p(4,3) = 0.742
p(4,2) = 0.939
p(4,1) = 0.997

p(3,8) = 0.000 (0.0004)
p(3,7) = 0.003
p(3,6) = 0.014
p(3,5) = 0.060
p(3,4) = 0.191
p(3,3) = 0.453
p(3,2) = 0.778
p(3,1) = 0.973

p(2,8) = 0.000 (0.000005)
p(2,7) = 0.000 (0.00007)
p(2,6) = 0.000 (0.0007)
p(2,5) = 0.006
p(2,4) = 0.035
p(2,3) = 0.152
p(2,2) = 0.443
p(2,1) = 0.837

(needless to say, for example, p(7,8) + p(8,7) is not equal to 1)

what do you feel about these numbers??