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is 8000
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integraI wrote
at 12:25 AM, Thursday January 14, 2010 EST |
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leeeroy jenkins wrote
at 11:53 AM, Friday January 15, 2010 EST aah true-- the sequence must end with the oldest post.
so you could get 4156237 in the right order by just bumping 3 then 2 then 1 because 4567 are in the right order already... |
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leeeroy jenkins wrote
at 11:54 AM, Friday January 15, 2010 EST Q to the mothafuckin ED
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Machoke wrote
at 12:11 PM, Friday January 15, 2010 EST actually that would be reverse order. in your example you would have to bump 2,3,4,5,6,7 in that order to get it to the right order.
7,3,6,2,5,1,4 however, becomes 7, 6, 5, 4, 3, 2, 1 after you bump 4, 5, 6, 7 |
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leeeroy jenkins wrote
at 12:14 PM, Friday January 15, 2010 EST I was trying to get it to 1234567
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greekboi wrote
at 1:03 PM, Friday January 15, 2010 EST props to int for getting a pretty healthy # of responses on this thread
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skrumgaer wrote
at 1:20 PM, Friday January 15, 2010 EST 4156237 gives rise to the multi-post-with-the-same-q situation that I am working on.
At the start, post 4 has a q value of 3 which is the highest value. The q rule says that 3 bumps are necessary. Incidentally, q can be negative. In my original post, where I said "cumulative", I should have said "net", because "cumulative" might imply positive sums only. After the first bump, we have 3415627. The q of all the numbers jumped went down by 1 and the q of post 3 increased by 5 to a value of +2. Since q is conserved, the increase in q of the bumped post equals the number of jumped posts, which is 5. The highest value of q is now 2, which is shared by posts 3 and 4. If we have a sequence of posts of the same q, the q rule is to be applied to the youngest of the sequence, and any operation that affects it will affect all the others in the same way. We now bump the 2, and get 2341567. The highest value of q is now 1, and is shared by posts 2, 3, and 4. The q rule is applied to post 2, and the last remaining bump is of the 1. If we consider the sequence 132, the post with the highest q is post 3, with a q of 1. But we cannot apply the q rule, since the post with the highest q is not in the top position. So we will have to apply the p rule. |
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integraI wrote
at 2:30 PM, Friday January 15, 2010 EST majority of my threads do well.
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the full monte wrote
at 2:39 PM, Friday January 15, 2010 EST except those empty ones you make so that you can post the 8000th discussion post. like half of those flared out.
what im saying is chase should bumb them with an alt. |
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Machoke wrote
at 3:44 PM, Friday January 15, 2010 EST i think skrum deserves the credit for this post. it woulda died a while ago without the math challenge.
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integraI wrote
at 3:45 PM, Friday January 15, 2010 EST yeah but I was the muse that sparked the skrum post therefore it is my thread.
and yeah, that's why I said majority and not all. |