Forum
average dice roll
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wishbone wrote
at 7:48 AM, Tuesday March 1, 2011 EST
someone with a math background explain to me why because each face of the die has the same percent chance of falling face up that anyone would believe that the "average dice roll should be 3.5"
With a standard of 1, and an equal distribution around the numbers 1-6, (F+L)/2 = 3.5? is this right??? but I think I am failing to account for something am I? Each face has a (1/6) chance of being rolled, and you have a (1/2) Chance for numbers 1-3 and a (1/2) chance of numbers 4-6,, is this still 3.5???? I mean won't massive statistics show that no one is rolling at/above 3.5 all the time? Isn't it more of a limit equation about chances and time rather than probability and statistics? |
Replies 1 - 3 of 3
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Boner Oiler wrote
at 7:54 AM, Tuesday March 1, 2011 EST 1+2+3+4+5+6=21/6=3.5
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Karsten4130 wrote
at 8:03 AM, Tuesday March 1, 2011 EST I asked Watson, it really is 3.5
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Man in a Van wrote
at 8:16 AM, Tuesday March 1, 2011 EST It relates to Expectancy.
E=np E=(1x1/6)+(2x1/6)+(3x1/6)... etc So E=3.5 You can also look at it as the sum of a sequence of rolls divided by the number of rolls. You will still get 3.5 |
