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I need some help...
trendz wrote
at 7:20 PM, Wednesday November 4, 2009 EST
Math test was extended so we can finish up in class tomorrow. This was the only one I didn't know... I've tried to solve it a few times, but no luck yet.

Anyone think they can solve it?


In a certain two digit number, the units digit is 24 less than three times the sum of the digits. If the digits are reversed, the new number is 18 more than the original number. Find the two digit number.



Replies 1 - 7 of 7
Pixel-Dust wrote
at 8:02 PM, Wednesday November 4, 2009 EST
I am not sure that I completely understand the first part of your question, but...

57 is 18 less than 75, which is the the digits reversed.

5+7=12 12x3=36 36 is 24 more than 12, which is the sum of 5+7.

leeeroy jenkins wrote
at 8:23 PM, Wednesday November 4, 2009 EST
No, it's 46. Units digit is only the 2nd number, not the sum of the numbers.

4+6=10
10x3= 30
30-24 = 6 (the units digit)

64-46= 18
the half monte wrote
at 9:13 PM, Wednesday November 4, 2009 EST
yes nice job leeroy
dfiend wrote
at 10:03 PM, Wednesday November 4, 2009 EST
Yep.

If you need to show work, this is how I solved it:

The original number is n.

To represent n as 2 separate digits, I just used n=xy and wrote the equation in terms of x and y.

By the stipulations set forth in the first sentence, you can write: y = 3(x+y) - 24

That simplifies as: y = -(3/2)x + 12

The original number is only 2 digits and by looking at the leading coefficient of x (-(3/2)), you should realize that each x is a factor of 2. In fact, there are only 4 possible combinations of x and y: 29, 46, 63, & 80. Reverse the digits and viola, 64 is 18 more than 46.

There's a more rigorous explanation, and you can actually pull out the pattern for each digit. Hint: 2, 4, 6, 8 = all possible variations of x | 9, 6, 3, 0 = all possible variations of y.
Shevar wrote
at 2:49 AM, Thursday November 5, 2009 EST
you can use a more straight forward approach.

first of all represent the number you are looking for in terms of its digits, i.e. 10a+b with a being the first digit ("ten's place") and b being the second digit ("one's place").

now you write your information into equations.

the units digit (b in our case) is 24 less then three times the sum of the digits (a+b).

->I: b=3*(a+b)-24

if the digits are reversed, the new number (10b+a) is 18 more than the original number (10a+b).

->II: 10b+a=10a+b+18

equation II looks easier to solve, so we start with that one. we subtract 1a and 1b on both sides.

II: 9b=9a+18

and divide by 9

II: b=a+2

inserting that into equation I yields

a+2=3*(a+a+2)-24

simplifying that leads to

a=4 and since a=b-2 (II) b=6

=> the two digit number is 46.
dr. zoidberg 69 wrote
at 3:58 AM, Thursday November 5, 2009 EST
(+487 for 1st and +451 for dominance)
Rank: 9th Score: +938 to 9406◆.
dr. zoidberg 69 finishes 1st in round 15
Gurgi wrote
at 6:38 AM, Thursday November 5, 2009 EST
shit nice, my best is still jjust 750 i cant farm with all these ppl complaining
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