1/(2C1*5C43C2*YOURMOM)

SNAPE KILLS DUMBLEDORE

1 in 18

Snape kills dumbledore?!?!?!

Hmm, I was thinking more like a > 5%.

Can you give me *your* averages for each?

Phoenix37's turn
l.o.s.e.r. defended 3v8: 13 to 23 (5,3,5 to 1,1,6,4,3,1,3,4)
l.o.s.e.r. defeated 4v8: 20 to 18 (6,3,5,6 to 2,1,1,1,2,1,4,6)
l.o.s.e.r. defeated 3v5: 12 to 8 (3,4,5 to 1,2,1,1,3)
l.o.s.e.r. defended 2v5: 7 to 14 (4,3 to 3,1,2,5,3)

l.o.s.e.r.'s turn
Phoenix37 defended 5v4: 13 to 15 (5,4,2,1,1 to 3,3,4,5)
3 days ago



what're the odds on this one?

I made it 1 in 100

with the odds of winning all three just over 1 in 3

well the 4vs 8 is a 0.6 percent chance, the 3 vs8 is a .1 percent chance the 3 vs 5 is a 5 percent chance and the last one is 2.2 percent lol

Ph for the president?

Yo again ;)

"l.o.s.e.r. defeated 4v8: 20 to 18 (6,3,5,6 to 2,1,1,1,2,1,4,6)
l.o.s.e.r. defeated 3v5: 12 to 8 (3,4,5 to 1,2,1,1,3)"
There's a link to the wiki to the left of the game with a table at the bottom, for some reason there's a probability table on kdice wikipedia too:
4v8: 0.6%
3v5: 6.1%
I'm not saying 100% those numbers are right but if they're wrong then someone should be able to prove what the correct numbers are?

Anyway, for this case *given* that you have lost a 4v8 (which is 0.6%) you have a 6.1% chance of losing your 3v5 attack.

To clarify, winning 2vs6 is only about 0.1% But winning a 2vs6 *given* that you have already won a 2vs6 is *still* just 0.1%. 2vs6 is a very rare roll but don't be shocked if it happens twice in a row to someone. If you want to be shocked you have to say "I bet my next two 2vs6's shall both lose" and then do it. If one happens *given that the other has happened* then it's only 0.1%

Some people have won the lottery more than once I believe? It's possible. But if someone says "I've never won the lottery but I will win it twice" they're crazy.

I can only guess that you're saying bad dice made "loser" lose the first roll and the broken system made Phoenix's odds of winning the next roll > 6.1%. When I analyze the individual dice on those rolls and the ones on my profile page I do not see a rigged dice pattern occurring. I'm trying to help you prove whether or not it's broken --because I want an accurate probability table-- but what else do you want me to try besides my eighty 4vs3 rolls?

All the best!

odds for the first set:

0.044

4.4%

odds for 2nd set.

l.o.s.e.r. defeated 4v8: 20 to 18 (6,3,5,6 to 2,1,1,1,2,1,4,6)
l.o.s.e.r. defeated 3v5: 12 to 8 (3,4,5 to 1,2,1,1,3)

in series: is

0.000366

0.03%